xavier hodges
xavier_h
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@P vs Point() problem March 8, 2018, 10:03 p.m.
Thank you tamte and vusta. I understand now.
@P vs Point() problem March 8, 2018, 7:49 p.m.
If that's the case, then why does
vector vec = set(1,1,1);
@P = @P+vec;
@P = @P-vec;
work the same way as the original
vector vec = set(1,1,1);
@P += vec;
@P -= vec;
yet acts different than
vector vec = set(1,1,1);
@P = point(0, “P”, @ptnum)+vec;
@P = point(0, “P”, @ptnum)-vec;
don't @P and point(0, “P”, @ptnum) do the same thing?
vector vec = set(1,1,1);
@P = @P+vec;
@P = @P-vec;
work the same way as the original
vector vec = set(1,1,1);
@P += vec;
@P -= vec;
yet acts different than
vector vec = set(1,1,1);
@P = point(0, “P”, @ptnum)+vec;
@P = point(0, “P”, @ptnum)-vec;
don't @P and point(0, “P”, @ptnum) do the same thing?
@P vs Point() problem March 8, 2018, 4:06 p.m.
I'm trying to transform some points in a point wrangle and
vector vec = set(1,1,1);
@P += vec;
@P -= vec;
returns points to their starting position as expected, but
vector vec = set(1,1,1);
@P = point(0, “P”, @ptnum)+vec;
@P = point(0, “P”, @ptnum)-vec;
gives different results, as if the first transform didn't do anything.
why are the results different? am I using point() wrong? sorry if this is too common a question.
vector vec = set(1,1,1);
@P += vec;
@P -= vec;
returns points to their starting position as expected, but
vector vec = set(1,1,1);
@P = point(0, “P”, @ptnum)+vec;
@P = point(0, “P”, @ptnum)-vec;
gives different results, as if the first transform didn't do anything.
why are the results different? am I using point() wrong? sorry if this is too common a question.