vector pos = point(0, "P", 6);
int npts = nearpoints(0, pos, 1.5);

printf("%s\n", npts);

foreach(int npt; npts){
if(npt == 6 || npt == 1){
removevalue(npts, npt);
}
}

printf("%s\n", npts);

===========result：
{6, 1, 5, 7, 11}
{1, 5, 7, 11}


Why point 1 cannot be removed

Hi,

You shouldn't modify the array you are looping over when using foreach loop. You don't have to loop over the elements like that to remove values. Just do like this:


Or loop over the elements to remove:

You remove 6, array is now {1,5,7,11}, next iteration is performed on the second element of the array, 5, so 1 is never iterated upon.

动画师_
Hi,

You shouldn't modify the array you are looping over when using foreach loop. You don't have to loop over the elements like that to remove values. Just do like this:

removevalue ( npts, 6 );
removevalue ( npts, 1 );

Or loop over the elements to remove:

int elements [ ] = { 6, 1 };
foreach ( int element; elements )
    removevalue ( npts, element );

I understand, thank you very much！

Tanto
You remove 6, array is now {1,5,7,11}, next iteration is performed on the second element of the array, 5, so 1 is never iterated upon.

thank you very much