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onmk2
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Edit editable node inside HDA from outside the HDA? 2020年12月4日14:24
I'm also searching how to do that.
I'm not sure but Node tab > Editable Nodes might work.
https://www.sidefx.com/forum/topic/53135/#post-238837 [www.sidefx.com]
I'm not sure but Node tab > Editable Nodes might work.
https://www.sidefx.com/forum/topic/53135/#post-238837 [www.sidefx.com]
Procedural implementation of EditSop's "Align Handle: Component" ? 2020年1月16日20:41
I found that I can use Edit Sop > Transform parameter > Local Frame > Component.
https://www.sidefx.com/docs/houdini/nodes/sop/edit.html#parameters [www.sidefx.com]
https://www.sidefx.com/docs/houdini/nodes/sop/edit.html#parameters [www.sidefx.com]
Procedural implementation of EditSop's "Align Handle: Component" ? 2019年6月2日20:34
I made a mistake in calc matrix, it must be not @P*AI, but AI*@P.
but the problem remains. How Houdini decide handle direction of EditSop?
please see scale_tangent_and_normal.hipnc.
but the problem remains. How Houdini decide handle direction of EditSop?
please see scale_tangent_and_normal.hipnc.
vector T = prim(0, "Tangent", pointprims(0, @ptnum)[0]); vector N = prim(0, "N", pointprims(0, @ptnum)[0]); vector B = prim(0, "BiTangent", pointprims(0, @ptnum)[0]); vector R0 = set(T[0], N[0], B[0]); vector R1 = set(T[1], N[1], B[1]); vector R2 = set(T[2], N[2], B[2]); matrix3 A = set(R0, R1, R2); matrix3 AI = invert(A); // scale shape in the coordinate system whose basis is Tangent, Normal, BiTangent v@Pdash = AI * @P; @Pdash[0] = @Pdash[0] * ch("./parmx"); @Pdash[1] = @Pdash[1] * ch("./parmy"); @Pdash[2] = @Pdash[2] * ch("./parmz"); // find result in the coordinate system whose basis is X:{1,0,0} Y:{0,1,0} Z:{0,0,1} @P = A * @Pdash;