Hi everyone! I'm wondering if we can find the top Nth primitives with the longest length. For example, if I have 10 primitives with 4 having a longer length than the other 6. I can used "measure" node and "group expression" (@length > 0.5), but if I tweak a certain node before those ones, I need to change the expression value from the "group expression" node to choose the correct primitives. Is there any way to just choose the top 4 longest length so I don't need to keep changing the value from the "group expression" node?

use Sort SOP to sort by your length attribute and check Reverse to start from largest
then Blast SOP to keep just first N primitives

Oh my, that totally works! Thank you so much for the help!