VEX Regex Captured Group Syntax
AlanZ Member
40 posts Joined: Feb. 2018 Offline
Feb. 11, 2020 2:13 p.m.
I'm trying to do some regex stuff in VEX, but couldn't figure out how to use captured groups.
The
help page for re_replace() [
www.sidefx.com ] says that $1 syntax is used. I tried:
string foo = "H18" ;
s@bar = re_replace (r"H([0-9]+)" , "Houdini $1" , foo );
// desired result: 'Houdini 18'
// actual result: 'Houdini'
which ignores the ‘$1’. What am I doing wrong?
tamte Member
9416 posts Joined: July 2007 Offline
Feb. 11, 2020 2:23 p.m.
try this
string foo = "H18" ;
s@bar = re_replace (r"H([0-9]+)" , r"Houdini \1" , foo );
Tomas Slancik
AlanZ Member
40 posts Joined: Feb. 2018 Offline
Feb. 11, 2020 2:33 p.m.
tamte string foo = "H18" ;
s@bar = re_replace (r"H([0-9]+)" , r"Houdini \1" , foo );
That works perfect. Thank you so much!
ayoburgess Member
37 posts Joined: June 2008 Offline
Jan. 5, 2021 11:37 a.m.
tamte string foo = "H18" ;
s@bar = re_replace (r"H([0-9]+)" , r"Houdini \1" , foo );
This tip just saved me a bunch of time. Thank you. I'm curious how you figured this out, is this just something that's incorrect in the docs or is it explained somewhere else?
Thanks again
tamte Member
9416 posts Joined: July 2007 Offline
Jan. 7, 2021 11:41 a.m.
I think it's just standard regex way to use numbred backreference, not really unique to Houdini, so I guess it's just a typo in docs
Tomas Slancik
