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Check if a point have any neighbors

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Tashmika_VFX
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Joined: March 2023
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Hello guys.

I have a VEX problem. I want learn a way to check my points have certain count of neighbors (I specify like let's say 3) within a given search radius (Donno this is correct, but something like neighborcount). If that point doesn't have certain amount of neighbors, i want to delete that point.

For example point 24 (red circle), I want to check if that point has 3 neighbors within the radius (blue circle). So it found only one. So, the point 24 will be deleted.

And I want to do this to all points (For loop type)

Can someone please help me ?

Thank you. Have a nice day.

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Enivob
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Review the docs on nearpoint and nearpoints. It should get there, along with removepoint.
https://www.sidefx.com/docs/houdini/vex/functions/nearpoints.html [www.sidefx.com]
Edited by Enivob - Aug. 28, 2023 14:50:08
Using Houdini Indie 20.0
Windows 11 64GB Ryzen 16 core.
nVidia 3050RTX 8BG RAM.
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eaniix
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attribute wrangles (except detail wrangles) are forloops already anyway because eg a point wrangle executes the given code for each point.

this should solve your answer, you can use the created slider to control the search radius

float maxdist = chf('maxdist'); //create slider for search radius

int neighbors[] = nearpoints(0, @P, maxdist); //create an array listing all neighbors within the search radius
removevalue(neighbors, @ptnum); //remove itself from array
int numberOfNeighbors = len(neighbors); //get number of neighbors

if(numberOfNeighbors < 3){
    removepoint(0, @ptnum); //delete point if it has less than 3 neighbors
}
Edited by eaniix - Aug. 29, 2023 05:56:22
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